assuming they all have different values, then yes, the average should be different between the 2 comparisons. however, if you were to use the same values for xxx1/2 and 3, then of course, the average would be the same.Korattt wrote: ↑Tue Mar 23, 2021 11:06 amnot sure if I’ve found a bug or not but working out two sets of averages as a stored value with using identical stored values doesn’t work, 2nd stored value as an average displays the same average as the 1st stored value
i.e.
SV’s
xxx1
xxx2
SV average of the two above = xyz
SV’s
xxx1 (as above)
xxx2 (as above)
xxx3
SV average of the three above= xyz (should be different)
.. any clues?
i'm sure you're not doing this -but just wanted to clarify
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