Relative Odds Condition - Is this right.

[Frogmella]

I want to place a bet on the favourite only when the second favourite's odds are within 1.

e.g. Betfair's Favourite is 3, Betfairs seconds favourite must be lower than 4.

I'm confused by the more thans and less thans so I need to know if this is doing what I think it is:

Condition.jpg

Can anyone confirm?

[MemphisFlash]

i think you may have that the wrong way round, i think it should be less than, otherwise what you consider to be the favourite is actually the second favourite

[Niko]

Maybe easier to set it as conditions? Back when position 1 is <3.0 but only if position 2 is <4.0?

[Frogmella]

i think you may have that the wrong way round, i think it should be less than, otherwise what you consider to be the favourite is actually the second favourite

For these purposes it doesn't matter who the favourite actually is, as long as the second favourite at the time less than 1 odds behind.

[Frogmella]

Maybe easier to set it as conditions? Back when position 1 is <3.0 but only if position 2 is <4.0?

I can't see any condition that would allow me to do this. Do you have an example?

[Niko]

Maybe easier to set it as conditions? Back when position 1 is <3.0 but only if position 2 is <4.0?

I can't see any condition that would allow me to do this. Do you have an example?

At work so don't quote me but think it's Fixed Odds Condition?

[Frogmella]

Maybe easier to set it as conditions? Back when position 1 is <3.0 but only if position 2 is <4.0?

I can't see any condition that would allow me to do this. Do you have an example?

At work so don't quote me but think it's Fixed Odds Condition?

No, that can't do it I'm afraid, thanks for trying to help.

[foxwood]

I think the OP is correct provided the rule is running on the favourite

translates to me as ...

Place bet if the selection's (fav 1) Back price (3) is > the back price (4-1) of selection in position 2 (fav 2)

ie if 3 > (4-1) = 3 > 3 = false so no bet placed

3.5 and 4 would place a bet because 3.5 > (4-1) = 3.5 > 3 = true

Not sure if you could use 0.99 for the minus instead of 1 - that would then bet when the odds were 3 & 4 or closer

Try in practice mode ?