My question is I want to make my own betting average when odds comes in my favour. So I want to laid player B at 0.5 how
For example:
Player A odds is 0.6
Player B odds is 1.66
And after sometime odds changed
Player A odds is 0.9
Player B odds is 1.1
I laid player A @ 0.6 $1000 and back @ 0.9 $1275 so now on player A I am winning $547.5 and on player B I am loosing $275. So my average is 0.5022. now it means I laid player B at 0.5022.
I did this calculation manually I want to make it on a excel sheet.
Guys please help me on this
Thanks
Desired betting average on profit and loss
viewtopic.php?t=8660azfyazfy wrote: ↑Sun Jun 20, 2021 9:44 pmMy question is I want to make my own betting average when odds comes in my favour. So I want to laid player B at 0.5 how
For example:
Player A odds is 0.6
Player B odds is 1.66
And after sometime odds changed
Player A odds is 0.9
Player B odds is 1.1
I laid player A @ 0.6 $1000 and back @ 0.9 $1275 so now on player A I am winning $547.5 and on player B I am loosing $275. So my average is 0.5022. now it means I laid player B at 0.5022.
I did this calculation manually I want to make it on a excel sheet.
Guys please help me on this
Thanks
viewtopic.php?t=13077
And you don’t want to just press the green up button on Bet Angel? Or set a target green all in guardian?
I’m struggling with your precise question and I fear a potential language and syntax barrier.
So are you asking this.
What are the odds of player B that if you layed play B for 275 you would produce a win of 547.50?
275/ x = 547.50
275 = 547.5x
X = 275/547.5
X = 0.5022
Am I right that you want to determine the back stake to apply at the relevant point to produce 0.25?
If so the formula is as follows
Bs= (Ls - 0.25LoLs)/(1-0.25Bo)
Where
Bs is the back stake
Ls is the lay stake
Lo is the lay odds (as you have presented them ie already reduced by 1)
Bo is the back odds (again as you have presented them)
Using your fixed amounts from above you get
Bs = (1000 - 0.25 x 0.6 x 1000)/(1 - 0.25 x 0.9)
Bs = 1096
So if you back at 1096 your win result is 386 and your loss result is 96. It’s as if you laid 96 at 0.25.
Is that what you are trying to achieve?
If so the formula is as follows
Bs= (Ls - 0.25LoLs)/(1-0.25Bo)
Where
Bs is the back stake
Ls is the lay stake
Lo is the lay odds (as you have presented them ie already reduced by 1)
Bo is the back odds (again as you have presented them)
Using your fixed amounts from above you get
Bs = (1000 - 0.25 x 0.6 x 1000)/(1 - 0.25 x 0.9)
Bs = 1096
So if you back at 1096 your win result is 386 and your loss result is 96. It’s as if you laid 96 at 0.25.
Is that what you are trying to achieve?
azfyazfy wrote: ↑Sun Jun 20, 2021 9:44 pmMy question is I want to make my own betting average when odds comes in my favour. So I want to laid player B at 0.5 how
For example:
Player A odds is 0.6
Player B odds is 1.66
And after sometime odds changed
Player A odds is 0.9
Player B odds is 1.1
I laid player A @ 0.6 $1000 and back @ 0.9 $1275 so now on player A I am winning $547.5 and on player B I am loosing $275. So my average is 0.5022. now it means I laid player B at 0.5022.
I did this calculation manually I want to make it on a excel sheet.
Guys please help me on this
Thanks